线性代数求解!答:a2,a3线性无关(因为a2,a3,a4线性无关),所以对于任意系数c4,c5, 使得c4a2 + c5a3 =0,则必有c4=c5=0 a1,a2,a3线性相关,则存在不全为0的系数c1,c2,c3使得 c1a1 +c2 a2 + c3 a3 =0 如果c1=0,则根据前式,c2=c3=0与假设矛盾,所以c1不等于0 所以a1 = -(c2/c1) a2 - (c3...
线性代数,求解答:显然此时系数矩阵行列式等于0,才有非零解 显然a=0时,系数矩阵行列式为0(每一列都相等)此时,解得基础解系是 (1,0,0...0)T (0,1,0...0)T ... (0,0,0...1)T 通解是k1(1,0,0...0)T +k2(0,1,0...0)T +... +kn(0,0,0...1)T 其中ki是不全为0的常数。下面...