如题所述
方法如下,请作参考:
这几个都 是幂函数的积分,
下面就可以直接套公式了
解答见下图:
integral1/(x sqrt(x)) dx = -2/sqrt(x) + constant
integral(x^2 - 1/(3 sqrt(x))) dx = 1/3 (x^3 - 2 sqrt(x)) + constant
integral(2^x/3^x - 1/x + 1/x^2) dx = -1/x - log(x) - (2/3)^x/log(3/2) + constant