(x^2+1)/(x+3)^2 = [(x+3)^2-(6x+8)]/(x+3)^2
= 1 - (6x+18-10)/(x+3)^2
= 1 - 6/(x+3) + 10/(x+3)^2
I = â«e^xdx - 6â«e^xdx/(x+3) +10â«e^xdx/(x+3)^2
= e^x - 6â«e^xdx/(x+3) -10â«e^xd[1/(x+3)]
= e^x - 6â«e^xdx/(x+3) -10e^x/(x+3) +10â«e^xdx/(x+3)
= e^x -10e^x/(x+3) +4â«e^xdx/(x+3)
e^x/(x+3) çåå½æ°ä¸æ¯åçå½æ°ã请éå°å·çåé¢ã
温馨提示:答案为网友推荐,仅供参考