aï¼n+1ï¼=2Ã3çn次æ¹+(-1)çn+1次æ¹Ã(ln2-ln3)+(-1)çn+1次æ¹Ã(n+1)Ãln3
è¿ä¸ªçå¼å å»åæ¥çå¼ï¼å½n为å¥æ°ï¼aï¼n+1ï¼+an=6^n+6^(n-1)+ln3äºæ¯6aï¼n+1ï¼-6^(n+1)+6an-6^n=6ln3,a(1)=ln2
æ¢å
tï¼n+1ï¼+tï¼nï¼=6ln3ï¼tï¼1ï¼=6ln2-6
tï¼2ï¼=6ln3-6ln2+6ï¼tï¼3ï¼=6ln2-6è¿ä¸ªæ°å循ç¯ï¼æ以tï¼nï¼=6ln2-6ï¼n为å¥æ°
tï¼nï¼=6ln3-6ln2+6ï¼n为å¶
å¾6an-6^n=6ln2-6ï¼n为å¥æ°
åå°è¿æ¥ï¼æ±å¤§ç¥æ¥å¸®ä¸
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