具体回答如图所示:
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一个函数,可以存在不定积分,而不存在定积分,也可以存在定积分,而没有不定积分。连续函数,一定存在定积分和不定积分。若有跳跃、可去、无穷间断点,则原函数一定不存在,即不定积分一定不存在。
扩展资料:
含有a+bx的积分公式主要有以下几类:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/9a504fc2d5628535567921529eef76c6a7ef632c?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/8b13632762d0f703c8f066af06fa513d2697c507?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/91529822720e0cf3bb9fbd880446f21fbe09aa5d?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/f31fbe096b63f6241835ca708944ebf81a4ca35d?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/d009b3de9c82d15818d5aac28e0a19d8bc3e426a?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
如果一个函数f 可积,那么它乘以一个常数后仍然可积。如果函数f和g可积,那么它们的和与差也可积。
如果一个函数f在某个区间上黎曼可积,并且在此区间上大于等于零。那么它在这个区间上的积分也大于等于零。如果f勒贝格可积并且几乎总是大于等于零,那么它的勒贝格积分也大于等于零。