|f(b)-f(a)|小于等于 (b-a)^2/4|f“(克色)|
t1,t2为什么 不可以是 a,b
追答t1, t2 是根据泰勒展开得到的。 取a,b 只是一种近似,没法判断大小。
追问(f''(t1) - f''(t2))/2小于等于max{|f''(t1)|, |f''(t2)|}怎么推的
追答|(f''(t1) - f''(t2))/2|
<=( |(f''(t1)|+|f''(t2)|)/2
<=(max{|f''(t1)|, |f''(t2)|} +max{|f''(t1)|, |f''(t2)|} )/2
= max{|f''(t1)|, |f''(t2)|}