设f(x)=x
3-2,用二分法求零点x
0.
f(1)=-1<0,f(2)=6>0,则x
0在区间(1,2)
f(1)=-1<0,f(1.5)=
>0,则x
0在区间(1,1.5)
f(1.25)=-
<0,f(1.5)=
>0,则x
0在区间(1.25,1.5)
f(1.25)=-
<0,f(1.375)>0,则x
0在区间(1.25,1.375)
f(1.3125)<0,f(1.375)>0,则x
0在区间(1.3125,1.375)
f(1.3125)<0,f(1.34375)>0,则x
0在区间(1.3125,1.34375)
f(1.3125)<0,f(1.328125)>0,则x
0在区间(1.3125,1.328125)
f(1.3125)<0,f(1.3203125)>0,则x
0在区间(1.3125,1.3203125)
f(1.3125)<0,f(1.31640625)>0,则x
0在区间(1.3125,1.31640625)
f(1.3125)<0,f(1.314453125)>0,则x
0在区间(1.3125,1.314453125)
∴
的近似值=1.31.