解ï¼âµxy'+y=y(lnx+lny)
==>(xy)'=yln(xy)
==>d(xy)/dx=(xy)ln(xy)/x
==>d(xy)((xy)ln(xy))=dx/x
==>d(ln(xy))/ln(xy)=dx/x
==>â«d(ln(xy))/ln(xy)=â«dx/x
==>lnâln(xy)â=lnâxâ+lnâCâ (Cæ¯éé¶å¸¸æ°)
==>ln(xy)=Cx
==>lny+lnx=Cx
==>lny=Cx-lnx
â´æ¤æ¹ç¨çé解æ¯lny=Cx-lnxã
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