数学等差数列问题,有点难求详细过程谢谢
数学等差数列问题,有点难求详细过程谢谢谢谢啦
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这题怎么做,等差数列的题目。数学,很急。求解详细过程答:(1)a3=10,a6=22 所以,a6=a3+(6-3)d,22=10+3d,3d=12,d=4 an=a3+(n-3)d=10+4(n-3)=4n-2 (2)a1,a2-m,a3-m构成等比数列 a1=4-2=2,a2=4x2-2=6 所以,(a2-m)^2=a1(a3-m)(6-m)^2=2(10-m)m^2-12m+36=20-2m m^2-10m+16=0 (m-2)(m-8)=0 m=2或m=...