这个题怎么求2阶导数

Question

如题所述

Answer 1

方法如下，
请作参考：

Answer 2

解答如下

Answer 3

可以用公式求，
y''(x)=(y''(t)x'(t)-x''(t)y'(t))/x'³(t)
然后分别求出x'(t),y'(t),x''(t)和y''(t)即可

Answer 4

(2) (f(x^2))' 链式法则 =f'(x^2) . (x^2)' =f'(x^2) . (2x) =2x.f'(x^2) (f(x^2))'' 2阶导数=1阶导数再求导数 =((f(x^2))')' =(2x.f'(x^2))' 链式法则 =2[ x.【f'(x^2)】' + f'(x^2). (x)']=2[ x f''(x^2).(x^2)' + f'(x^2)] =2[ x f''(x^2).

Answer 5

可以用公式求，
y''(x)=(y''(t)x'(t)-x''(t)y'(t))/x'³(t)
然后分别求出x'(t),y'(t),x''(t)和y''(t)即可