解:
1)
当0≤x<1时,
Φ(x)=∫(0,x) f(t)dt = ∫(0,x) xdt = x/2
2)
当1≤x<2时,
Φ(x)=∫(0,1) f(t)dt +∫(1,x) f(t)dt
=∫(0,1) tdt +∫(1,x) t² dt
=(1/2) + (1/3)(x³-1)
=(1/3)x³ + (1/6)
3)
当x≥2时,
Φ(x)=∫(0,1) f(t)dt +∫(1,2) f(t)dt
=17/6
由2)可知,当x=2时,就是3)因此:
x/2 0≤x<1
Φ(x)=
(1/3)x³ + (1/6) 1≤x≤2
lim(x→1-) Φ(x) = lim(x→1-) x/2 = 1/2
lim(x→1+)Φ(x) = lim(x→1+) (1/3)x³ + (1/6) = 1/2
因此,在x=1时,Φ(x)连续
综合,Φ(x)在(0,2)上连续
追问太感谢了。
你可以再帮我解决一下这两个问题吗,谢谢。
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