解ï¼è®¾AP=tï¼BQ=2tï¼åPB=6-tï¼QC=12-2t
PQ^2=(6-t)^2+2t^2
DQ^2=(12-2t)^2+36
DP^2=t^2+144
ï¼1ï¼å½PQ^2+DQ^2=DP^2æ¶ï¼æ
(6-t)^2+2t^2+(12-2t)^2+36=t^2+144ï¼åç®å¾t^2-10t+12=0ï¼è§£å¾t=5-æ ¹å·13ï¼5+æ ¹å·13ä¸åé¢æèå»ï¼
ï¼2ï¼å½PQ^2+DP^2=DQ^2æ¶ï¼æ
(6-t)^2+2t^2+t^2+144ï¼(12-2t)^2+36ï¼åç®å¾36t=0ï¼è§£å¾t=0ï¼ä¸é¢æä¸ç¬¦èå»ã
æ以å½ç§»å¨(5-æ ¹å·13)ç§æ¶ï¼ä¸è§å½¢PDQ为ç´è§ä¸è§å½¢ã
温馨提示:答案为网友推荐,仅供参考