c:\abc.dat中的内容为:
10.2
23.0
25.1
14.6
32.6
452.3
12.3
69.3
45.6
123.2
排序后为:
10.2
12.3
14.6
23.0
25.1
32.6
45.6
69.3
123.2
452.3
Press any key to continue
#include <stdio.h>
main()
{
int i,j;
FILE *fp;
float tmp,a[10];
fp = fopen("c:\\abc.dat","r");
printf("c:\\abc.dat中的内容为:\n");
for (i=0;i<10;i++)
{
fscanf(fp,"%f",&a[i]);
printf("%.1f\n",a[i]);
}
printf("\n");
for (i=0;i<10-1;i++)
{
for (j=0;j<10-i-1;j++)
{
if (a[j]>a[j+1])
{
tmp = a[j];
a[j] = a[j+1];
a[j+1] = tmp;
}
}
}
printf("排序后为:\n");
for (i=0;i<10;i++)
{
printf("%.1f\n",a[i]);
}
}
温馨提示:答案为网友推荐,仅供参考