1mol石墨完全燃烧后可放出393.5KJ的热量,下列热化学方程式正确的是( )A.C(s)+O2(g)=CO2(g);△H=+393.5kJ/molB.C(s)+12O2(g)=CO(g);△H=-393.5kJ/molC.C+O2=CO2;△H=-393.5kJ/molD.C(s)+O2(g)=CO2(g);△H=-393.5kJ/mol