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    • 已知隐函数XY=e(X+Y)次方,求y'和dy,

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    第1个回答  2022-07-18
    y+xy'=（1+y'）e^（x+y）则y'=（y-e^(x+y)）/(e^(x+y)-x),dy=（y-e^(x+y)/(e^(x+y)-x)dx
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