一道数学题哦

Question

已知2乘以X的平方，加上2乘以x，减去55，等于0
求（2X的5次方，加上2X的4次方，减去53X的3次方，减去57X，加上54）的2004次方的值
还有（可以不回答）怎么在计算机上打平方、几次方的呢？我不会
希望大家能看懂。

Answer 1

2x^2+2x-55=0,求(2x^5+2x^4-53x^3-57x+54)^2004.

2x^5+2x^4-53x^3-57x+54
=x^3(2x^2+2x-55)+x(2x^2+2x-55)-(2x^2+2x-55)-1
=0+0+0-1
=-1
(2x^5+2x^4-53x^3-57x+54)^2004
=(-1)^2004
=1

Answer 2

2x^2+2x-55=0,求(2x^5+2x^4-53x^3-57x+54)^2004.

2x^5+2x^4-53x^3-57x+54
=x^3(2x^2+2x-55)+x(2x^2+2x-55)-(2x^2+2x-55)-1
=0+0+0-1
=-1
(2x^5+2x^4-53x^3-57x+54)^2004
=(-1)^2004
=1

Answer 3

2x^2+2x-55=0,求(2x^5+2x^4-53x^3-57x+54)^2004.

2x^5+2x^4-53x^3-57x+54
=x^3(2x^2+2x-55)+x(2x^2+2x-55)-(2x^2+2x-55)-1
=0+0+0-1
=-1
(2x^5+2x^4-53x^3-57x+54)^2004
=(-1)^2004
=1

Answer 4

2x^2+2x-55=0,求(2x^5+2x^4-53x^3-57x+54)^2004.

2x^5+2x^4-53x^3-57x+54
=x^3(2x^2+2x-55)+x(2x^2+2x-55)-(2x^2+2x-55)-1
=0+0+0-1
=-1
(2x^5+2x^4-53x^3-57x+54)^2004
=(-1)^2004
=1