y' = -2x
A(-1, 0)处的
切线: y = (-2)(-1)(x + 1) = 2(x + 1)
B(1, 0)处的切线: y = (-2)*1(x - 1) = -2(x - 1)
二者交于C(0, 1)
切线和曲线所围成图形的面积 S = ∫₋₁⁰[2(x + 1) - (1 - x²)]dx + ∫₀¹[(1 - x²) - 2(x + 1)]dx
= (x³/3 + x² + x)|₋₁⁰ + (-x³/3 - x² - x)|₀¹
= 1/3 + 1/3
= 2/3
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