ã计ç®ã
1ãæ»´å®å°19.98 ml æ¯çpH = 4.3ï¼å¡«ç©ºï¼
åå¼ è®¡ç®ï¼[H+] = (20.00-19.98)/39.98]x0.1000 = 5.00x10^-5 , pH = 4.3
2ãæ»´å®å°20.02 ml æ¯çpH = 9.7ï¼å¡«ç©ºï¼
åå¼ è®¡ç®ï¼[OH+] = (20.02-20.00)/40.02]x0.1000 = 5.00x10^-5 , pOH = 4.3
å pH = 9.7
追é®æ°´ç离å积æä¹æ±ç
追çæ°´ç离å积 Kw = 1.0 x10^-14 pKw = 14 .00
ã计ç®ãw = [H+][OH-]/[H20]=[H+][OH-]=(1.0 x10^-7)(1.0 x10^-7)=1.0 x10^-14