此题拟用最基本的方法解决。遍历3~100,考察能否可被3或5整除,将能被3或5整除的数输出。代码如下(为输出版面整齐,每行限20个数):
#include "
stdio.h"
int main(int argc,char *argv[]){
int i,l;
for(l=0,i=3;i<=100;i++)//遍历3~100
if(i%3==0 || i%5==0)//判断能被3或5整除才输出
printf(++l%20 ? "%4d" : "%4d\n",i);
if(l%20)
printf("\n");
return 0;
}
运行结果如下:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/f703738da9773912bc905fc8f2198618377ae2e1?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)