自定义一个函数求阶乘,主函数中用一个for循环遍历1~10调用自定义函数,并将返回值累加就可解此题。代码如下:
#include "stdio.h"
int f(int n){//自定义求n!的函数
int t;
for(t=1;n>1;t*=n--);
return t;
}
int main(int argc,char *argv[]){
int s,i;
for(s=i=0;i<10;s+=f(++i));//遍历1~10调用f求阶乘累加到s
printf("1!+2!+...+10! = %d\n",s);
return 0;
}
运行结果如下:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/902397dda144ad3472388a2edaa20cf430ad8597?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)