怎样求三角函数sin的特殊值？

Question

如题所述

Answer 1

三角函数在特定角度时有特殊的值，常见的特殊值如下：

正弦函数（sin）的特殊值：

sin(0) = 0
sin(π/6) = 1/2
sin(π/4) = √2/2

sin(π/3) = √3/2
sin(π/2) = 1
sin(2π/3) = √3/2
sin(3π/4) = √2/2
sin(5π/6) = 1/2
sin(π) = 0
sin(7π/6) = -1/2
sin(5π/4) = -√2/2
sin(4π/3) = -√3/2
sin(3π/2) = -1
sin(5π/3) = -√3/2
sin(7π/4) = -√2/2

sin(11π/6) = -1/2

余弦函数（cos）的特殊值：

cos(0) = 1
cos(π/6) = √3/2
cos(π/4) = √2/2
cos(π/3) = 1/2
cos(π/2) = 0
cos(2π/3) = -1/2
cos(3π/4) = -√2/2
cos(5π/6) = -√3/2
cos(π) = -1
cos(7π/6) = -√3/2
cos(5π/4) = -√2/2
cos(4π/3) = -1/2
cos(3π/2) = 0
cos(5π/3) = 1/2
cos(7π/4) = √2/2

cos(11π/6) = √3/2

正切函数（tan）的特殊值：

tan(0) = 0
tan(π/6) = 1/√3

tan(π/4) = 1
tan(π/3) = √3
tan(π/2) = 无穷大
tan(2π/3) = -√3
tan(3π/4) = -1

tan(5π/6) = -1/√3
tan(π) = 0
tan(7π/6) = 1/√3
tan(5π/4) = 1
tan(4π/3) = √3

tan(3π/2) = 无穷大

tan(5π/3) = -√3

tan(7π/4) = -1
tan(11π/6) = -1/√3

这些特殊值可以在三角函数的图表或计算器中找到。