1.=lim(x趋向于0)[1+tanx-(1+sinx)]/[x(ln(1+x)-x)([(1+tanx)开根号]+[(1+sinx)开根号)]
=lim(x趋向于0)[tanx(1-cosx)]/[2x(ln(1+x)-x)]
=lim(x趋向于0)[x^2/2]/[2(ln(1+x)-x)]
=lim(x趋向于0)[2x]/[4(-x/(1+x))]
=-1/2
2.y'=2/3[(x+1)^(-1/3)]*[(x-5)^2]+2[(x+1)3分之2次方]*[(x-5)]
=(x-5)(17x+5)/[3(x+1)^(1/3)]=0
-->极小值x=5,极大值x=-5/17
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