c语言输入某年某月某日,求下一天的日期？

Question

如题所述

Answer 1

#include <stdio.h>

int main()

{

int year1,month1,day1,year2,month2,day2;

int day[12] = {31,28,31,30,31,30,31,31,30,31,30,31};

printf("Please input year-month-day : ",year1,month1,day1);

scanf("%d-%d-%d",&year1,&month1,&day1);

if((year1 % 400 == 0) || (year1 % 4 == 0 && year1 % 100 != 0))

    day[1] = 29;

if(month1 < 1 || month1 > 12 || day1 < 1 || day1 > day[month1 - 1])

{

printf("ERROR!\n");

return 0;

}

if(month1 == 12 && day1 == day[month1 - 1])

{

year2 = year1 + 1;

month2 = 1;

day2 = 1;

}

else if(month1 != 12 && day1 == day[month1 - 1])

{

year2 = year1;

month2 = month1 + 1;

day2 = 1;

}

else if(day1 != day[month1 - 1])

{

year2 = year1;

month2 = month1;

day2 = day1 + 1;

}

printf("The next day is %d-%d-%d.\n",year2,month2,day2);

return 0;

}

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