逻辑函数化简F=(A'+B'+C')(C+D)，'为非

Question

如题所述

Answer 1

F=(A'+B'+C')(C+D)
=(A'+B'+C')C+(A'+B'+C')D
=A'C+B'C+A'D+B'D+C'D
=A'C+B'C+(A'CD+A'C'D)+(B'CD+B'C'D)+C'D
=A'C+B'C+C'D