C语言求1！+2！+3！+4!+5!+6!+7!+8!+9!+10！用do语句？

Question

如题所述

Answer 1

代码资料：

#include "stdio.h"

int main(int argc,char *argv[]){

int s,n,t;

s=0,t=n=1;

do

s+=t*=n;

while(n++<10);

printf("1!+2!+3!+...+10!=%d\n",s);

return 0;

}

Answer 2

int i = 0;
int j = 1;
int reslut = 1;
int sum = 0;

do
{
i++;

for (j = 1; j <= i; j++)
{
reslut = reslut * j;
}
sum = sum + reslut;
reslut = 1;
}
while (i < 10);