51单片机4个数码管显示程序

Question

#include<REG51.H>
char led_mod[]={0x76,0x86};
void delay (unsigned int time);
void main(){
char led_point=0;
while(1){
P3=5-led_point;
P2=led_mod[led_point];
led_point=1-led_point;
delay(30);
}
}
void delay(unsigned int time){
unsigned int j=0;
for(;time>0;time--)
for(j=0;j<125;j++);
}
这个是两个动态数码管显示的程序，，4个的怎么编写，，显示1234，

Answer 1

#include<reg52.h> //52系列单片机头文件
#define uchar unsigned char //宏定义
#define uint unsigned int
sbit dula=P2^6; //申明u1锁存器的锁存端
sbit wela=P2^7; // u2
uchar num1,num2;
uchar code table[]={ //数组定义
0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
uchar code aable[]={ //位选数组定义
0xfe,0xfd,0xfb,0xf7,0xef,0xdf};
void delays(uint); //子函数申明

void main()
{
while(1)
{
for(num1=0;num1<48;num1++) //6个数循环显示
{
wela=1; //打开u2锁存端
P0=aable[num1%6]; //送入位选信号
wela=0; //关闭u2锁存端
// delays(1);
dula=1; //打开u1锁存端
P0=table[num1%16]; //送入段选信号
dula=0; //关闭u1锁存端
delays(1);
}
}
}
/*---------主函数-----------------------------------------------*/

void delays(uint xs)
{
uint i,j,k;
for(i=xs;i>0;i--)
for(j=1000;j>0;j--)
for(k=110;k>0;k--);
}
/*----------------延时程序-----------------------------------------------*/

Answer 2

#include<REG51.H>

char led_mod[] = { 0xf9, 0xa4, 0xb0, 0x99 };    /*共阳数码管显示编码*/
char led_bit[] = { 0x01, 0x02, 0x04, 0x08 };    /*位选信号编码*/

void delay (unsigned int time);

void main()
{
    char led_point = 0;
    while(1)
    {
        /*  共阳数码管  */
        P3 = 0x00;                 /*关位选，防止显示混乱*/
        P2 = led_mod[led_point];   /*送显示编码*/
        P3 = led_bit[led_point];   /*开位选*/
        
        /*  共阴数码管  */          
/*      P3 = 0xff;                  /*关位选，防止显示混乱*/
/*      P2 = ~led_mod[led_point];   /*送显示编码*/
/*      P3 = ~led_bit[led_point];   /*开位选*/
        
        led_point++;               /*4位循环标志*/
        if ( led_point == 4 )
            led_point = 0;
        
        delay(4);   /*延时点亮4ms*/
                    /*人的视觉停留效果，要求扫描周期不超过18ms为最佳*/
    }
}

/* 延时函数，延时 time ms */
void delay(unsigned int time)
{
    unsigned char j;
    for( ; time>0; time-- )
        for( j=0; j<125; j++ );
}

追问

你这个是什么程序，后面有每步的解释？

本回答被提问者采纳

Answer 3

#include<REG51.H>
char led_mod[]={0xf9,0xa4,0xb0,0x99};
void delay (unsigned int time);
void main(){
char led_point=0;
while(1){
switch(led_point)

{
case 0:P3=0x08;P2=led_mod[led_point];break;

case 1:P3=0x04;P2=led_mod[led_point];break;
case 2:P3=0x02;P2=led_mod[led_point];break;
case 3:P3=0x01;P2=led_mod[led_point];break;
default:break;

}

delay(5);

led_point++;

led_point%=4

}
}
void delay(unsigned int time){
unsigned int j=0;
for(;time>0;time--)
for(j=0;j<125;j++);
}

Answer 4

uchar code table1[]={0x7f,0xbf,0xdf,0xef,0xf7,0xfb,0xfd,0xfe};
void delay(uchar z)
{ uchar x,y;
for(x=z;x>0;x--)
for(y=0;y<1250;y++);
}
void main()
{
uchar i,j;
while(1)
{
for(j=0;j<8;j++)
{
P2=table1[j];
wei=1;
wei=1;
wei=0;
P2=table[j]; duan=1; delay(10);
P2=0;
duan=0; } } }