è¿æ¯è«å°æ³æµå®æ°¯ç¦»åå«é计ç®
Ag+ +Cl- =AgClï¼å½å°è¾¾ç»ç¹æ¶ï¼çæé¬é
¸é¶ç 红è²æ²æ·æ示ç»ç¹ã
NaCl%=ï½[n(NaCl)ÃM(NaCl)]/Sï½Ã100%
=ï½[c(AgNO3)ÃV(AgNO3)ÃM(NaCl)]/Sï½Ã100%
=ï½[0.1005Ã31.04Ã(10^-3)Ã58.44]/0.1875}Ã100%
=97.23%
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