用c语言编一个程序 要求1:输入一个年份，输出是在屏幕上显示该年的日历。假定输入的年份在1940

Question

用c语言编一个程序 要求1:输入一个年份，输出是在屏幕上显示该年的日历。假定输入的年份在1940-2040年之间 2: 输入年月，输出该月的日历 3:输入年月日，输出距今天还有多少天，星期几，是否是公历节日 4:某人自1990年1月1日开始，三天打鱼，两天晒网，输出一个1990年以后的日期，输出他这一天是打鱼还是晒网

Answer 1

#include<stdio.h>
#include<stdlib.h>

char* month_str[]={"January","February","March","April","May","June","July","August","September","October","November","December"};
char* week[]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};

int IsLeapYear(int year) /*find out the year is leap year or not*/
{
if((year%4==0&&year%100!=0)||(year%400==0)) //这里是判断是否是闰年的
return 1; //如果是闰年就返回值1
else
return 0;//不是的话返回0

}
int month_day(int year,int month) //这个函数用来判断这年的月分有多少天的
{
int mon_day[]={31,28,31,30,31,30,31,31,30,31,30,31};
if(IsLeapYear(year)&&month==2) /*判断是判断是否是闰年，如果是闰年而且这个月是2月那这个月有29天*/
return 29;
else
return(mon_day[month-1]);

}
int DaySearch(int year,int month,int day) /*这个函数是计算输入的日期对应的星期*/
{
int c=0;
float s;
int m;
for(m=1;m<month;m++)
c=c+month_day(year,m); //这是计算输入的月分的累计天数
c=c+day; //计算日期在这一年中是第几天
s=year-1+(int)(year-1)/4+(int )(year-1)/100+(int)(year-1)/400-40+c; /*这是计算日期对应的星期公式，这个公式可在网上查到*/
return ((int)s%7); //与上语句同属计算日期对应的星期
}

int PrintAllYear(int year)/*这个函数是用来输出全年的日历*/
{
int temp;
int i,j;
printf("\n\n%d Calander\n",year);
for(i=1;i<=12;i++)
{
printf("\n\n%s(%d)\n",month_str[i-1],i); //输出月分名称
printf("0 1 2 3 4 5 6 \n");
printf("S M T W T F S \n\n");
temp=DaySearch(year,i,1);
for(j=1;j<=month_day(year,i)+temp;j++)
{
if(j-temp<=0)
printf(" ");
else if(j-temp<10)
printf("%d ",j-temp);
else
printf("%d ",j-temp);

if(j%7==0)
printf("\n");
}
}
return 0;
}

int main()
{
int option,da;
char ch;
int year,month,day;
printf("Copyright @ 2005 TianQian All rights reserved!:):):)");
printf("\n\nWelcome to use the WanNianLi system!\n");

while(1)
{
printf("\nPlease select the service you need:\n"); //用来提示选择执行功能
printf("\n1 Search what day the day is"); //选择1时，用来计算这一天是星期几
printf("\n2 Search whether the year is leap year or not"); //计算是否这年是闰年
printf("\n3 Print the calander of the whole year"); //输入全年的日历
printf("\n4 Exit\n"); //选择退出程序
scanf("%d",&option);

switch(option) //用来选择执行
{
case 1:
while(1)
{
printf("\nPlease input the year,month and day(XXXX,XX,XX):"); //提示输入
scanf("%d,%d,%d,%c",&year,&month,&day); //读入数据
da=DaySearch(year,month,day); //调用DaySearch()函数来计算是星期几
printf("\n%d-%d-%d is %s,do you want to continue?(Y/N)",year,month,day,week[da]);
fflush(stdin); //刷新输入缓冲区
scanf("%c",&ch);
if(ch=='N'||ch=='n')
break;
}
break;
case 2: /*当为2时，进行相应运算*/
while(1)
{
printf("\nPlease input the year which needs searched?(XXXX)");
scanf("%d",&year);
if(IsLeapYear(year))
printf("\n%d is Leap year,do you want to continue?(Y/N)",year);
else
printf("\n%d is not Leap year,do you want to continue(Y/N)?",year);
fflush(stdin);
scanf("%c",&ch);
if(ch=='N'||ch=='n')
break;
}
break;
case 3: /*当为3时运行相应的运算*/
while(1)
{
printf("\nPlease input the year which needs printed(XXXX)");
scanf("%d",&year);
PrintAllYear(year);
printf("\nDo you want to continue to print(Y/N)?");
fflush(stdin);
scanf("%c",&ch);
if(ch=='N'||ch=='n')
break;
}
break;
case 4:
fflush(stdin);
printf("Are you sure?(Y/N)");
scanf("%c",&ch);
if(ch=='Y'||ch=='y')
exit(1);
break;
default:
printf("\nError:Sorry,there is no this service now!\n");
break;
}

}

return 0;
}
我只有这个代码追问

谢谢

追答

呵呵，用你超高的智商去修改代码吧！