C语言编写个人所得税？

Question

如题所述

Answer 1

代码文本：

#include "stdio.h"

int main(int argc,char *argv[]){

double x,tax;

printf("Please enter the number salary, negative end...\n");

while(scanf("%lf",&x),x>=0){

if(x>=5000)

tax=(x-5000)*0.2+4200*.03;

else if(x>=800 && x<5000)

tax=(x-800)*.03;

else

tax=0;

printf("You should pay %.2f yuan.\n",tax);

}

return 0;

}

Answer 2

#include <stdio.h>
#include <stdlib.h>
int jishu(double x)
{
 if(0<x&&x<=500)
  return 1;
 else if(500<x&&x<=2000)
  return 2;
 else if(2000<x&&x<=5000)
  return 3;
 else if(5000<x&&x<=20000)
  return 4;
 else if(20000<x&&x<=40000)
  return 5;
 else if(40000<x&&x<=60000)
  return 6;
 else if(60000<x&&x<=80000)
  return 7;
 else if(80000<x&&x<=100000)
  return 8;
 else
  return 9;
}
main()
{
 double rate[10]={0.0,0.05,0.1,0.15,0.2,0.25,0.3,0.35,0.4,0.45};
 int a[10]={0,0,25,125,375,1375,3375,6375,10375,15375};
 double n,m,l;
 int i;
 printf("请输入工资：");
 scanf("%lf",&l);
 if(l<=3500)
  printf("您不用交税\n");
 else
 {
  n=l-3500.0;
  i=jishu(n);
  m=n*rate[i]-a[i];
  printf("应缴个人所得税：%.2lf\n实发工资额：%.2lf\n",m,l-m);
 }
}

这是按你说的计算方法

Answer 3

通常，这使用平行的if语句就能够实现的。

#include "stdio.h"

int main()

{ float x,y=0;

  scanf("%f",&x);

  if(x>5000)

  {y=(x-5000)*0.2;

   x=5000;

  }

  if(x>800)

  y+=(x-800)*0.03;

  printf("%.2f\n",y);

  return 0;

}

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