A和溴发生加成反应的产物是1,2-二溴丙烷,所以A是丙烯,根据产物CH
3COCHO,可以知道B是1,2-二溴丙烷水解的产物,得到了含有两种醇羟基的有机物质,B是CH
3CH(OH)CH
2OH,醛可以和银氨溶液发生银镜反应,所以C是CH
3COCOONH
4,酸化后得到D为:CH
3COCOOH,根据加聚产物聚丙烯酸钠,可以得出G是丙烯酸钠,则F是丙烯酸,所以E是CH
3COCOOH和氢气加成以后得到的醇,即为:CH
3CH(OH)COOH,该醇可以发生消去反应.
(1)A的名称是丙烯,B是CH
3CH(OH)CH
2OH,含有的官能团的名称是羟基,故答案为:丙烯;羟基;
(2)E的结构简式是CH
3CH(OH)COOH,故答案为:CH
3CH(OH)COOH;
(3)CH
3CH(OH)COOH转化为CH
2═CHCOOH的反应是消去反应,丙烯酸钠转化为聚丙烯酸钠的反应属于加聚反应,故答案为:消去反应;加聚反应;
(4)CH
3COCHO具有醛的性质,可以发生银镜反应,原理方程式为:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/810a19d8bc3eb1356dc0cf39a51ea8d3fd1f4428?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
+2Ag(NH
3)
2OH
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/7c1ed21b0ef41bd52854907652da81cb39db3d28?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
+3NH
3+2Ag↓+H
2O,
故答案为:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/810a19d8bc3eb1356dc0cf39a51ea8d3fd1f4428?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
+2Ag(NH
3)
2OH
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/7c1ed21b0ef41bd52854907652da81cb39db3d28?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
+3NH
3+2Ag↓+H
2O;
(5)F为丙烯酸,它的分子式为:C
3H
4O
2,它的同分异构体中,能与新制氢氧化铜在加热条件下反应生成红色沉淀,说明含有醛基,与NaOH溶液混合后滴入酚酞,加热,溶液颜色变浅,证明含羧基,所以结构简式为:HCOOCH=CH
2,故答案为:HCOOCH=CH
2.