解答:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/5fdf8db1cb134954235eae9e554e9258d0094a83?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
解:A、∵OD、OE分别是∠AOC、∠BOC的平分线,
∴∠DOE=
(∠BOC+∠AOC)=
∠AOB=60°.
故本选项叙述错误;
B、∵OD是∠AOC的
角平分线,
∴∠AOD=
∠AOC.
又∵OC是∠AOB内部任意一条射线,
∴∠AOC=∠EOC不一定成立.
故本选项叙述错误;
C、∵OD、OE分别是∠AOC、∠BOC的平分线,
∴∠BOE+∠AOD=∠EOC+∠DOC=∠DOE=
(∠BOC+∠AOC)=
∠AOB=60°.
故本选项叙述正确;
D、∵OC是∠AOB内部任意一条射线,
∴∠BOE=∠AOC不一定成立,
∴∠BOE=2∠COD不一定成立.
故本选项叙述错误;
故选:C.