第1个回答 2011-10-30
#include<stdio.h>
#include<conio.h>
void main()
{
while(1)
{
float a=0,b=0,c=0,key;
char d;
printf("输入四则运算表达式:\n");
scanf("%f%c%f",&a,&d,&b);
switch(d)
{
case'+': c=a+b;break;
case'-': c=a-b;break;
case'x':
case'*': c=a*b;break;
case'/': if(b>0) c=a/b;break;
default:break;
}
printf("%g%c%g=%g\n",a,d,b,c);
printf("Do you want to continue(Y|N)\n");
key =getch();
if(key=='n' || key=='N')
break;
}
}本回答被提问者采纳