谢谢
S下面=b×√2b/2/2x6=3√2b^2/2
计算S侧面.:过上面某边中点A向下面对应边中线作垂线A H,连接下边中点B即B H,A B则A B ,则△A B H为Rt ,AH=h, BH=√2(b-a)/2
A B=√(h^2+(√2(b-a)/2)^2
=V(4h^2+2(b-a)^2)/2
S侧=(b+a)×√(4h^2+2(b-a)^2)/2/2X6
=3(a+b)* (√(4h^2+2(b-a))/2
S表=3√2a^2/2+3√2b^2/2+3(a+b)X(√(4h^2+2(b-a)^2)/2
=3√2(a^2+b^2)/2+3(a+b)X(√(4h^2+2(b-a)^2)/2
(注b>a)
本回答被网友采纳