将AE平移到DF,连接BF,EF.
则四边形AEFD是平行四边形.
∴AD∥EF,AD=EF.
∵AC=√3BD,CD=√3AE
∴AC/BD=√3 CD/AE=CD/DF=√3
∴AC/BD=CD/DF
∵ ∠C=90°,
∴∠BDF=90°
∴ ∠C=∠BDF.
∴ △ACD∽△BDF
∴AD/BF=AC/BD=√3,∠1=∠2.
∴ EF/BF=AD/BF=√3
∵ ∠1+∠3=90°,
∴ ∠2+∠3=90°.
∴BF⊥AD .
∴BF⊥EF.
∴ 在Rt△BEF中,tan角BEF=BE/EF=√3/3.
∴ ∠APE=∠BEF =30°
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