特殊角的正弦余弦正切值，要全，满意就采纳！

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Answer 5

sin0°=0 sin30°=1/2 sin45°=√2/2 sin60°=√3/2 sin90°=1
cos0°=1 cos30°=√3/2 cos45°=√2/2 cos60°=1/2 cos90°=0
tan0°=0 tan30°=√3/3 tan45°=1 tan60°=√3
cot30°=√3 cot45°=1 cot60°=√3/3 cot90°=0追答

α=0°sinα=0 cosα=1 tαnα=0 cotα→∞ secα=1 cscα→∞

α=15°(π/12) sinα=(√6-√2)/4 cosα=(√6+√2)/4 tαnα=2-√3 cotα=2+√3 secα=√6-√2 cscα=√6+√2

α=22.5°(π/8) sinα=√(2-√2)/2 cosα=√(2+√2)/2 tαnα=√2-1 cotα=√2+1 secα=√(4-2√2) cscα=√(4+2√2)

α=30°(π/6) sinα=1/2 cosα=√3/2 tαnα=√3/3 cotα=√3 secα=2√3/3 cscα=2

α=45°(π/4) sinα=√2/2 cosα=√2/2 tαnα=1 cotα=1 secα=√2 cscα=√2

α=60°(π/3) sinα=√3/2 cosα=1/2 tαnα=√3 cotα=√3/3 secα=2 cscα=2√3/3

α=67.5°(3π/8) sinα=√(2+√2)/2 cosα=√(2-√2)/2 tαnα=√2+1 cotα=√2-1 secα=√(4+2√2) cscα=√(4-2√2)

α=75°(5π/12) sinα=(√6+√2)/4 cosα=(√6-√2)/4 tαnα=2+√3 cotα=2-√3 secα=√6+√2 cscα=√6-√2

α=90°(π/2) sinα=1 cosα=0 tαnα→∞ cotα=0 secα→∞ cscα=1

α=180°(π) sinα=0 cosα=-1 tαnα=0 cotα→∞ secα=-1 cscα→∞

α=270°(3π/2) sinα=-1 cosα=0 tαnα→∞ cotα=0 secα→∞ cscα=-1

α=360°(2π) sinα=0 cosα=1 tαnα=0 cotα→∞ secα=1 cscα→∞