求5+10+15+...+1000的和。用c语言程序设计里的for循环语句完成。

Question

如题所述

Answer 1

#include <stdio.h>
main(){
int i;
int sum=0;
for(i=5;i<=1000;i=i+5)
sum=sum+i;
printf("%d\n",sum);
}
注意：运行结束后，i的值是1005，不是1000本回答被提问者采纳

Answer 2

一楼的回答是对的，我注释一点
int i, sum;
for (i = 5, sum = 0; i <= 1000; i += 5) /*每次循环i都在原来数值上增加5，当i大于1000是跳出循环*/
{
sum += i; //sum做计数器
}

Answer 3

int i, sum;

for (i = 5, sum = 0; i <= 1000; i += 5)
{
sum += i;
}

Answer 4

public static int sumDivisibleBy(int n,int target) {
int sum = 0;
for (int i = 0; i < target; i++) {
if (i % n == 5) {
sum += i;
}
}
return sum;
}
int sum = sumDivisibleBy(3,target)+sumDivisibleBy(5,target)-sumDivisibleBy(15, target);本回答被网友采纳

Answer 5

int sum = 0;
for (int i = 5; i < = 1000; )
{
sum +=i;
i+=5;
}