求问一道高中化学题，急！http://m.baidu.com/from=1099a/bd_page_type=1/ssid=0/uid=0/baiduid=CB577EE21BA3F3C109DD56FCF29A4586/w=0_10_%E5%90%91%E7%AD%89%E9%87%8F%E7%9A%84NaOH%E6%BA%B6%E6%B6%B2%E4%B8%AD%E5%88%86%E5%88%AB%E9%80%9A%E5%85%A5CO2%E6%B0%94%E4%BD%93%E3%80%82%E5%9B%A0CO2%E7%9A%84%E9%80%9A%E5%85%A5%E9%87%8F%E4%B8%8D%E5%90%8C%EF%BC%8C%E5%BE%97%E5%88%B0%E7%BB%84%E5%88%86%E4%B8%8D%E5%90%8C%E7%9A%84%E6%BA%B6%E6%B6%B2M%E3%80%82%E8%8B%A5%E5%90%91M%E4%B8%AD%E9%80%90%E6%BB%B4%E5%8A%A0%E5%85%A5%E7%9B%90%E9%85%B8%EF%BC%8C%E4%BA%A7%E7%94%9F%E7%9A%84%E6%B0%94%E4%BD%93%E4%BD%93%E7%A7%AFV%EF%BC%88CO2%EF%BC%89%E4%B8%8E%E5%8A%A0%E5%85%A5%E7%9B%90%E9%85%B8%E7%9A%84%E4%BD%93%E7%A7%AFV%EF%BC%88HCl%EF%BC%89%E5%85%B3%E7%B3%BB%E5%A6%82%E4%B8%8B%EF%BC%8C%28%E6%B3%A8%EF%BC%9A%E2%91%A0%E5%81%87%E8%AE%BECO2%E5%85%A8%E9%83%A8%E9%80%B8%E5%87%BA/t=zbios/l=3/tc?ref=www_zbios&pu=sz%401320_480%2Ccuid%40C8AA80A160A07B06F0BC80A7E94DE2595624C9A87FGIRIQRBCE%2Ccua%40640_960_iphone_4.4.0.0_0%2Ccut%40iPhone3%252C1_5.1.1%2Cosname%40baiduboxapp%2Cctv%401%2Ccfrom%401001867a%2Ccsrc%40app_delimit_txt%2Cta%40zbios_1_5.1_6_&lid=14874349872787985645&order=1&vit=osres&tj=www_normal_1_0_10&m=8&srd=1&cltj=cloud_title&dict=20&sec=35502&di=0483ca28da1d17bb&bdenc=1&nsrc=D9bHNQEptyoA_yixCFOxXnANedT62v3IIQyNPWBX0TWxoo3tfeSlItgfEFXbNWiCJ5DhxWeCxBt8wXOj0G1ezBAx
分析：A曲线里面的溶质是：NaHCO3 (因为NaHCO3与盐酸反应比例是1:1，产生的二氧化碳也是1) B曲线里面的溶质是：NaHCO3、Na2CO3（盐酸先和碳酸钠反应生成碳酸氢钠，然后再和碳酸氢钠反应生成二氧化碳） C曲线里面的溶质是：Na2CO3（oa=ab,所以全部都是碳酸钠。） D曲线里面的溶质是：Na2CO3、NaOH（oa太长了，说明还有氢氧化钠没反应）