数学因式分解法解方程详细过程

Question

如题所述

Answer 1

11
1)[(3x-1)+13][(3x-1)-13]=0
(3x+12)(3x-14)=0
x=-4或x=14/3
2)[2(x-3)+5(x-2)][2(x-3)-5(x-2)]=0
(7x-16)(3x-4)=0
x=6/7或x=4/3
3)(x-3)[(x-3)+4x]=0
(x-3)(5x-3）＝0
x=3或x=3/5
4）[(2x-1)-2]^2=0
(2x-3)^2=0
2x-3=0
x=3/2

Answer 2

拿起一支笔，写上答案，完啦