大学数学跟高中数学有什么不同吗

Question

如题所述

Answer 1

∫ sinx/(1+sinx+cosx) dx
=∫sinx(sinx+cosx-1)/[(sinx+cosx+1)(sinx+cosx-1)] dx
=∫(sin^2x+sinxcosx-sinx)/[(sinx+cosx)^2-1] dx
=∫(sin^2x+sinxcosx-sinx)/(2sinxcosx) dx
=(1/2)∫sinx/cosx dx+(1/2)∫ dx-(1/2)∫1/cosx dx
=(-1/2)∫1/cosx d(cosx)+(1/2)∫ dx-(1/2)∫secx dx
=(1/2)x-(1/2)ln(cosx)+(1/2)x-(1/2)ln(secx+tanx)+C本回答被网友采纳