谁的导数是1╱sinx＋cosx.求解

Question

如题所述

Answer 1

　解：分享一种解法。∵1/(cosx+sinx)=(1/√2)/cos(x-π/4)=sec(x-π/4)/√2，
　　∴∫dx/(cosx+sinx)=(1/√2)∫sec(x-π/4)dx=(1/√2)ln丨sec(x-π/4)+tan(x-π/4)丨+C。供参考。本回答被网友采纳