如题所述
回答跟没回答是的
令x=sinz,dx=coszdz
∫dx/[x √(1-x2)]
=∫cosz/(sinz cosz)*dz
=(1/2)∫[(sinz cosz) (-sinz cosz)]/(sinz cosz)*dz
=(1/2)∫dz (1/2)∫d(cosz sinz)/(sinz cosz)*dz
=(1/2)z (1/2)ln|sinz cosz| C
=(1/2)(arcsinz) (1/2)ln|x √(1-x2)| C