第2个回答 2018-11-19
∫dx/sinx = ∫cscxdx = ln|cscx-cotx| + C
∫dx/cosx = ∫secxdx = ln|secx+tanx| + C
∫dx/(sinx)^2 = ∫(cscx)^2dx = -cotx + C
∫dx/(cosx)^2 = ∫(secx)^2dx = tanx + C
∫ f(1/√x)dx = x^2 + C, f(1/√x) = 2x = 2/(1/√x)^2,
f(u) = 2/u^2, ∫ f(x)dx = ∫2dx/x^2 = -2/x + C本回答被网友采纳