C语言求助~

这程序结果死活不对 不知道是哪里错了 望各位大师指点~
#include<stdio.h>

void aver(float *p,int n);

void search(float (*p)[4]);

void main()
{

void average(float *p,int n);

void search(float (*p)[4]);

int s[3][4]={{65,67,70,60},{80,87,90,81},{90,99,100,98}};

average(*s,12);

search(s,2);
}

void average(float *p,int n)
{
float *p_end;
float sum=0,aver;

p_end=p+n-1;

for(;p<=p_end;p++)
sum=sum+(*p);

aver=sum/n;

printf("the average is %5.2f\n",aver);
}

void search(float (*p)[4],int n)
{
int i;
printf("the score of NO. %d are:\n",n);
for(i=0;i<4;i++)
printf("%5.2f",*(*(p+n)+i));
}

第1个回答  2010-04-08
#include<stdio.h>

void average(float *p,int n);

void search(float (*p)[4],int n);

void int main()
{
float s[3][4]={{65,67,70,60},{80,87,90,81},{90,99,100,98}};

average(*s,12);

search(s,2);
}

void average(float *p,int n)
{
float *p_end;
float sum=0,aver;

p_end=p+n-1;

for(;p<=p_end;p++)
sum=sum+(*p);

aver=sum/n;

printf("the average is %5.2f\n",aver);
}

void search(float (*p)[4],int n)
{
int i;
printf("the score of NO. %d are:\n",n);
for(i=0;i<4;i++)
printf("%5.2f",*(*(p+n)+i));
}本回答被提问者采纳
第2个回答  2020-01-13
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