请设计二分算法,求x^3-x-1=0在区间【1,1.5】内的解(精确度为0.1)

如题所述

第1个回答  2014-03-08
解:令f(x) = x3– x – 1,求方程x3– x – 1 = 0在[1,1.5]内的解,由二分法可得:f(1) = 13– 1 – 1 = -1 < 0①,f(3/2) = (3/2)3 – (3/2) – 1 = 7/8 >0②,(1 + 3/2)/2= 5/4 = 1.25,f(5/4) = (5/4)3– (5/4) – 1 = -19/64 < 0③,所以方程x3 – x – 1 = 0在(5/4,3/2)内有解,(5/4 + 3/2)/2 = 11/8 = 1.375,f(11/8) = (11/8)3– (11/8) – 1 = 115/512 > 0④,所以方程x3 – x – 1 = 0在(5/4,11/8)内有解,(5/4 + 11/8)/2 = 21/16 = 1.3125,f(21/16) = (21/16)3– (21/16) – 1 = -211/4096 < 0⑤,所以方程x3 – x – 1 = 0在(21/16,11/8)内有解,(21/16 + 11/8)/2= 43/32 = 1.34375,f(43/32) = (43/32)3 – (43/32) – 1 = 2707/32768> 0⑥,所以方程x3– x – 1 = 0在(21/16,43/32)内有解,即原方程在(1.3125,1.34375)内有解,所以精确到0.1,本题的近似解为1.3 ;
解:4x + 5y + 2z= 30①,5x – 2y + 4z= 21②,①*2 + ②*5,可得33x + 24z =165 => 11x + 8z = 55 => z = (55 – 11x)/8 ≥ 0 => 55 – 11x ≥ 0 => 55 ≥ 11x => 0 ≤ x ≤ 5,检验可得:
1)x = 0时,z = (55 –11x)/8 = 55/8不是非负整数,舍去;
2)x = 1时,z = (55 –11x)/8 = 44/8 = 11/2不是非负整数,舍去;
3)x = 2时,z = (55 –11x)/8 = 33/8不是非负整数,舍去;
4)x = 3时,z = (55 –11x)/8 = 22/8 = 11/4不是非负整数,舍去;
5)x = 4时,z = (55 –11x)/8 = 11/8不是非负整数,舍去;
6)x = 5时,z = (55 –11x)/8 = 0,代入4x + 5y + 2z= 30,可得20 + 5y = 30=> 5y = 10 => y = 2,符合题意;
综上所述,原方程组的非负整数解为(x,y,z) = (5,2,0) 。
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