(1)某烃A 0.2mol在氧气中完全燃烧后,生成CO
2和H
2O各1.2mol,根据原子守恒可知A的分子式为C
6H
12,若该烃能使溴的四氯化碳溶液褪色且分子中所有碳原子共平面,则A为(CH
3)
2C=C(CH
3)
2,用系统命名法命名为:2,3-二甲基-2-丁烯,在一定条件下发生加聚反应的化学方程式为:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/3812b31bb051f81970d924f8d9b44aed2f73e780?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
故答案为:(CH
3)
2C=C(CH
3)
2;2,3-二甲基-2-丁烯;
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/3812b31bb051f81970d924f8d9b44aed2f73e780?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;
(2)含苯环的化合物B,其相对分子质量为104,碳的质量分数为92.3%,则分子中C原子数目=
=8、H原子数目=
=8,故B的分子式为C
8H
8,由于B含有苯环,则B为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/63d0f703918fa0ec123843bf259759ee3c6ddb80?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,分子中苯的平面与乙烯形成的平面可以处于同一平面,8个C原子都可能处于同一平面; 一定条件下,B与氢气反应,得到的化合物中碳的质量分数为85.7%,则生成物中C、H原子数目之比=
:
=1:2,则生成物结构简式为:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/908fa0ec08fa513d3a554b6c3e6d55fbb3fbd980?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,反应方程式为:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/63d0f703918fa0ec123843bf259759ee3c6ddb80?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
+4H
2![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/908fa0ec08fa513d3a554b6c3e6d55fbb3fbd980?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
故答案为:8;
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/63d0f703918fa0ec123843bf259759ee3c6ddb80?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
+4H
2![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/908fa0ec08fa513d3a554b6c3e6d55fbb3fbd980?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;
(3)化合物C经李比希法测得碳、氢、氧三种元素的质量比为为12:1:4,则分子中C、H、O原子数目之比=
:
:
=4:4:1,最简式为C
4H
4O,令分子式为(C
4H
4O)x,质谱法分析得知其相对分子质量为136,
则:68x=136,故x=2,则C的分子式为C
8H
8O
2,C的核磁共振氢谱有4个峰且面积之比 为1:2:2:3,氢原子数目分别为1、2、2、3,C分子中只含一个苯环且苯环上只有一个取代基,则含有一个CH
3,结合红外光谱可知侧链为-COOCH
3,故C为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/0df3d7ca7bcb0a46dcddac8b6863f6246a60af80?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,属于酯、芳香族化合物,
故答案为:C
8H
8O
2;
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/0df3d7ca7bcb0a46dcddac8b6863f6246a60af80?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;①⑥.