F与苏合香醇互为同系物,F为醇,则D为羧酸,D的相对分子质量通过质谱法测得为88,结合G的分子式可知,D的分子式为C
4H
8O
2,D的核磁共振氢谱显示只有三组峰,则D为2-甲基丙酸,结合合成转化图中的反应条件可知,A为2-甲基丙烯,B为2-甲基丙醇,C为2-甲基丙醛,D与F发生酯化反应生成G(C
13H
18O
2),则F为C
9H
12O,(4)中G中含有两个-CH
3,E可发生银镜反应,在催化剂存在下1mol E与2mol H
2可以反应生成F,所以E为C
9H
8O,则E的结构简式为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/b3fb43166d224f4a1b3cbda20af790529922d1de?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,F为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/359b033b5bb5c9ea4c56cd52d639b6003bf3b3de?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,则G为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/6159252dd42a28346103f8ba58b5c9ea14cebfde?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
(1)苏合香醇为C
6H
5CH(OH)CH
3,其分子式为C
8H
10O,由-OH和苯环可知,能发生取代、加成、氧化、消去反应,而不能发生水解、加聚反应,
故答案为:C
8H
10O;④⑥;
(2)由上述分析可知,A为2-甲基丙烯,故答案为:2-甲基丙烯;
(3)C与新制Cu(OH)
2悬浊液反应的化学方程式为:(CH
3)
2CHCHO+2Cu(OH)
2(CH
3)
2CHCOOH+Cu
2O↓+2H
2O,
故答案为:(CH
3)
2CHCHO+2Cu(OH)
2(CH
3)
2CHCOOH+Cu
2O↓+2H
2O;
(4)G中含有两个-CH
3,E可发生银镜反应,在催化剂存在下1mol E与2mol H
2可以反应生成F,所以E为C
9H
8O,则E的结构简式为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/b3fb43166d224f4a1b3cbda20af790529922d1de?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
故答案为:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/b3fb43166d224f4a1b3cbda20af790529922d1de?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;
(5)D与F反应的化学方程式为:(CH
3)
2CHCOOH+
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/359b033b5bb5c9ea4c56cd52d639b6003bf3b3de?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/08f790529822720e4d7e2c4b78cb0a46f31fabcb?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/6159252dd42a28346103f8ba58b5c9ea14cebfde?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
+H
2O,
故答案为:(CH
3)
2CHCOOH+
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/359b033b5bb5c9ea4c56cd52d639b6003bf3b3de?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/08f790529822720e4d7e2c4b78cb0a46f31fabcb?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/6159252dd42a28346103f8ba58b5c9ea14cebfde?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
+H
2O;
(6)F结构简式为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/359b033b5bb5c9ea4c56cd52d639b6003bf3b3de?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,其同分异构体符合:苯环上有3个取代基或官能团,显弱酸性,则侧链为-OH、-CH
3、-CH
2CH
3,若-CH
3、-CH
2CH
3相邻,-OH有4种位置,若-CH
3、-CH
2CH
3相间,-OH有4种位置,若-CH
3、-CH
2CH
3相对,-OH有2种位置,故共有10种,苯环上 3个取代基或官能团互不相邻,则该同分异构体为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/1b4c510fd9f9d72a31d4deacd72a2834359bbbcb?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,故答案为:10;
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/1b4c510fd9f9d72a31d4deacd72a2834359bbbcb?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
.