导数的题目

Question

导数的题目这题怎么解

Answer 1

d^2x/dy^2 =d/dy (dx/dy) =d/dy (1/y') “dx/dy = 1/(dy/dx) ” =[d/dx ( 1/y' ) ] . dx/dy “ 链式法则” = [-y''/(y')^2] . (1/y') =-y''/(y')^3本回答被网友采纳