编程:实现对4,9,5,2,7,17,11,8,3,1共10个整数由小到大排序答:include <stdio.h> //冒泡排序 void main(void){ int aa[10] = {4,9,5,2,7,17,11,8,3,1};int j=0;int i=10;while (i--){ j = 0;while (++j <= i){ if (aa[j-1] > aa[j]){ aa[j-1] ^= aa[j] ^= aa[j-1] ^= aa[j];} } } for (i=0;i<10;i+...