这个是将二次积分化为极坐标形式,但是r的范围不会确定,求一个详细的...答:角度属于[0,π/2]0<=x<=1 ; 0<=y<=1-x (将y用x替代)那么由0<=y<=1-x可知:0<=rcosθ<=1-rsinθ 解得:r∈(0,1/(c))此时积分方程=∫(0,1)dx∫(0,1-x)f(x,y)dy =∫∫Df(rsinθ,rcosθ)dθdr =∫(0,π/2)dθ∫(0,1/(sinθ+cosθ))f(rsinθ,rco...
怎么在MATLAB中画出x^2+y^2=1且y^2+z^2=1的图像答:[x,y,z]=cylinder(1,200);z=2.2*z-1.1;claa=0.3;mesh(x,y,z,'edgecolor','none','facecolor','r','facealpha',a)hold onmesh(z,x,y,'edgecolor','none','facecolor','g','facealpha',a)axis equal t=linspace(0,2*pi,200);x=cos(t);y=sin(t);z1=sqrt(1-y.^2);...