python 怎么快速获取嵌套列表内的每一个元素?答:aa = [[(55736,)], [(55739,)], [(55740,), (55801,)], [(55748,)], [(55783,), (55786,), (55787,), (55788,)], [(55817,), (55821,)], [(55818,)]]
利用python中的方法和函数提取给定列表[5,-7,2,-3,0]中的最大元素并删 ...答:list1=['5','8','-7','4','6','2','-3','0']max(list1)min(list1)abs(-7)